(\partial)/(\partial x)(3x^2-2xy-4y^2)

Lösung

\frac{\partial}{\partial x} (3 x^{2} - 2 x y - 4 y^{2})

6 x - 2 y

Schritte zur Lösung

\frac{\partial}{\partial x} (3 x^{2} - 2 x y - 4 y^{2})

Behandle

y

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2}) - \frac{\partial}{\partial x} (2 x y) - \frac{\partial}{\partial x} (4 y^{2})

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (2 x y) = 2 y

\frac{\partial}{\partial x} (4 y^{2}) = 0

= 6 x - 2 y - 0

Vereinfache

= 6 x - 2 y

\frac{d y}{d t} \cdot \frac{1}{4} + y = cos (t)

\int - \frac{1}{3} e^{- 3 t} d t

\frac{d}{d x} (3 x + e^{x})

\frac{\partial}{\partial y} (4 - x^{2} - 7 y^{2})

2 y^{^{''}} + 3 y^{^{'}} + y = t^{2} + 2 sin (t)