(4x+2y)dx+(2x+2y)dy=0

Lösung

(4 x + 2 y) d x + (2 x + 2 y) d y = 0

y = - x + - x^{2} + c_{1}, y = - x - - x^{2} + c_{1}

Schritte zur Lösung

(4 x + 2 y) d x + (2 x + 2 y) d y = 0

Solve exact ODE:

y = - x + - x^{2} + c_{1}, y = - x - - x^{2} + c_{1}

y = - x + - x^{2} + c_{1}, y = - x - - x^{2} + c_{1}

a re a x^{2} + y^{2} = 1, y = 1 - x

n = 1 \sum \infty \frac{3}{n ^{3}}

t an g e n t y = \frac{9}{x - 2}, (3, 9)

\int_{- 2}^{2} (- x^{2} + 4) d x

2 y^{^{''}} - 6 y^{^{'}} + y = 0