tangent y= 9/(sqrt(x-2)),(3,9)

解答

切线

y = \frac{9}{x - 2}, (3, 9)

y = - \frac{9}{2} x + \frac{45}{2}

求解步骤

计算

y = \frac{9}{x - 2}

的斜率:

\frac{d y}{d x} = - \frac{9}{2 ( x - 2 ) ^{\frac{3}{2}}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{9}{2}

找到斜率 m=

- \frac{9}{2}

且穿过

(3, 9)

的直线:

y = - \frac{9}{2} x + \frac{45}{2}

y = - \frac{9}{2} x + \frac{45}{2}

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