derivative 400-3P+4T+0.6A

Lösung

ableitung von

400 - 3 P + 4 T + 0.6 A

- 3

Schritte zur Lösung

\frac{d}{d P} (400 - 3 P + 4 T + 0.6 A)

Behandle

T, A

als Konstanten

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d P} (400) - \frac{d}{d P} (3 P) + \frac{d}{d P} (4 T) + \frac{d}{d P} (0.6 A)

\frac{d}{d P} (400) = 0

\frac{d}{d P} (3 P) = 3

\frac{d}{d P} (4 T) = 0

\frac{d}{d P} (0.6 A) = 0

= 0 - 3 + 0 + 0

Vereinfache

= - 3

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