4y^{''}+8y^'+3y=0

Lösung

4 y^{^{''}} + 8 y^{^{'}} + 3 y = 0

y = c_{1} e^{- \frac{t}{2}} + c_{2} e^{- \frac{3 t}{2}}

Schritte zur Lösung

4 y^{''} (t) + 8 y^{'} (t) + 3 y = 0

Solve linear ODE:

y = c_{1} e^{- \frac{t}{2}} + c_{2} e^{- \frac{3 t}{2}}

y = c_{1} e^{- \frac{t}{2}} + c_{2} e^{- \frac{3 t}{2}}

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