What is the derivative of (x^2/(x-3)) ?

The derivative of (x^2/(x-3)) is (x^2-6x)/((x-3)^2)

What is the first derivative of (x^2/(x-3)) ?

The first derivative of (x^2/(x-3)) is (x^2-6x)/((x-3)^2)

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\frac{d}{d x} (\frac{x ^{2}}{x - 3})

\frac{x ^{2} - 6 x}{( x - 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{x - 3})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} ) ( x - 3 ) - \frac{d}{d x} ( x - 3 ) x ^{2}}{( x - 3 ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (x - 3) = 1

= \frac{2 x ( x - 3 ) - 1 \cdot x ^{2}}{( x - 3 ) ^{2}}

Simplify

\frac{2 x ( x - 3 ) - 1 \cdot x ^{2}}{( x - 3 ) ^{2}} : \frac{x ^{2} - 6 x}{( x - 3 ) ^{2}}

= \frac{x ^{2} - 6 x}{( x - 3 ) ^{2}}

d er i v a t i v e (6 x + 5) (x^{2} - 3 x)

\int 9 x^{5} d x

\int sin (r^{2}) d r

\int cos (2 π t) d t

\frac{\partial}{\partial u} (u^{5} + v^{7})

What is the derivative of (x^2/(x-3)) ?
The derivative of (x^2/(x-3)) is (x^2-6x)/((x-3)^2)
What is the first derivative of (x^2/(x-3)) ?
The first derivative of (x^2/(x-3)) is (x^2-6x)/((x-3)^2)