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tangent f(x)=x^4-5x^2+4,\at x=2

解答

切线

f (x) = x^{4} - 5 x^{2} + 4, at x = 2

解答

y = 12 x - 24

求解步骤

找到切点:

(2, 0)

计算

f (x) = x^{4} - 5 x^{2} + 4

的斜率:

\frac{df ( x )}{d x} = 4 x^{3} - 10 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 12

找到斜率 m=

12

且穿过

(2, 0)

的直线:

y = 12 x - 24

y = 12 x - 24

作图

流行的例子

(dy)/(dx)-y/x =xe^x

\frac{d y}{d x} - \frac{y}{x} = x e^{x}

integral of (x^2)/(x^2-x+1)

\int \frac{x ^{2}}{x ^{2} - x + 1} d x

derivative of A*e^x

\frac{d}{d x} (A \cdot e^{x})

derivative f(x)=(x^5)/5-(4x^3)/3+4x

d er i v a t i v e f (x) = \frac{x ^{5}}{5} - \frac{4 x ^{3}}{3} + 4 x

tangent f(x)=7e^{-0.03x},\at x=9

t an g e n t f (x) = 7 e^{- 0.03 x}, at x = 9