(3x+6y)dx+(6x-8y3)dy=0

解

(3 x + 6 y) d x + (6 x - 8 y 3) d y = 0

y = - \frac{- 12 x + 432 x ^{2} - c _{1}}{48}, y = - \frac{- 12 x - 432 x ^{2} - c _{1}}{48}

解答ステップ

(3 x + 6 y) d x + (6 x - 8 y 3) d y = 0

完全 ODE を解く:

y = - \frac{- 12 x + 432 x ^{2} - c _{1}}{48}, y = - \frac{- 12 x - 432 x ^{2} - c _{1}}{48}

y = - \frac{- 12 x + 432 x ^{2} - c _{1}}{48}, y = - \frac{- 12 x - 432 x ^{2} - c _{1}}{48}