(7x+8)+(7y-7)y^'=0

解

(7 x + 8) + (7 y - 7) y^{^{'}} = 0

y = \frac{14 + 196 - 28 ( - c _{1} + 16 x + 7 x ^{2} )}{14}, y = \frac{14 - 196 - 28 ( - c _{1} + 16 x + 7 x ^{2} )}{14}

解答ステップ

(7 x + 8) + (7 y - 7) y^{'} (x) = 0

分離可能 ODE を解く:

y = \frac{14 + 196 - 28 ( - c _{1} + 16 x + 7 x ^{2} )}{14}, y = \frac{14 - 196 - 28 ( - c _{1} + 16 x + 7 x ^{2} )}{14}

y = \frac{14 + 196 - 28 ( - c _{1} + 16 x + 7 x ^{2} )}{14}, y = \frac{14 - 196 - 28 ( - c _{1} + 16 x + 7 x ^{2} )}{14}