(\partial)/(\partial x)(x^2-kxe^{3y}-3y^2)

Lösung

\frac{\partial}{\partial x} (x^{2} - k x e^{3 y} - 3 y^{2})

2 x - k e^{3 y}

Schritte zur Lösung

\frac{\partial}{\partial x} (x^{2} - k x e^{3 y} - 3 y^{2})

Behandle

k, y

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (k x e^{3 y}) - \frac{\partial}{\partial x} (3 y^{2})

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (k x e^{3 y}) = k e^{3 y}

\frac{\partial}{\partial x} (3 y^{2}) = 0

= 2 x - k e^{3 y} - 0

Vereinfache

= 2 x - k e^{3 y}

t an g e n t f (x) = x^{2} - 5, (2, - 1)

t an g e n t \frac{( 5 x - 4 )}{x - 1}

\frac{d}{d x} (- s t)

\int \frac{1}{x ^{2} x} d x

\int \frac{1}{x ( x + 1 ) ^{2}} d x