What is the integral from-1 to 1 of-1 ?

The integral from-1 to 1 of-1 is -2

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integral from-1 to 1 of-1

\int_{- 1}^{1} - 1 d x

- 2

Solution steps

\int_{- 1}^{1} - 1 d x

Integral of a constant:

\int a d x = a x

= [(- 1) x]_{- 1}^{1}

Simplify

= [- x]_{- 1}^{1}

Compute the boundaries:

- 2

= - 2

\int (x - \frac{1}{x})^{2} d x

\frac{\partial}{\partial x} (e^{- 1})

x \to 3 lim (x^{2} - 6 x + 8)

\int \frac{1}{t ^{2} 4 - t ^{2}} d t

\frac{\partial}{\partial x} (- 13 e^{x} sin (y) - 14 y)