integral of ((x^2-8))/(8x)

Lösung

\int \frac{( x ^{2} - 8 )}{8 x} d x

\frac{x ^{2}}{16} - ln ∣ x ∣ + C

Schritte zur Lösung

\int \frac{x ^{2} - 8}{8 x} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{8} \cdot \int \frac{x ^{2} - 8}{x} d x

Multipliziere aus

\frac{x ^{2} - 8}{x} : x - \frac{8}{x}

= \frac{1}{8} \cdot \int x - \frac{8}{x} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{8} (\int x d x - \int \frac{8}{x} d x)

\int x d x = \frac{x ^{2}}{2}

\int \frac{8}{x} d x = 8 ln ∣ x ∣

= \frac{1}{8} (\frac{x ^{2}}{2} - 8 ln ∣ x ∣)

Vereinfache

\frac{1}{8} (\frac{x ^{2}}{2} - 8 ln ∣ x ∣) : \frac{x ^{2}}{16} - ln ∣ x ∣

= \frac{x ^{2}}{16} - ln ∣ x ∣

Füge eine Konstante zur Lösung hinzu

= \frac{x ^{2}}{16} - ln ∣ x ∣ + C

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