derivative of ln(3x^2+5)

Lösung

\frac{d}{d x} (ln (3 x^{2} + 5))

\frac{6 x}{3 x ^{2} + 5}

Schritte zur Lösung

\frac{d}{d x} (ln (3 x^{2} + 5))

Wende die Kettenregel an:

\frac{1}{3 x ^{2} + 5} \frac{d}{d x} (3 x^{2} + 5)

= \frac{1}{3 x ^{2} + 5} \frac{d}{d x} (3 x^{2} + 5)

\frac{d}{d x} (3 x^{2} + 5) = 6 x

= \frac{1}{3 x ^{2} + 5} \cdot 6 x

Vereinfache

\frac{1}{3 x ^{2} + 5} \cdot 6 x : \frac{6 x}{3 x ^{2} + 5}

= \frac{6 x}{3 x ^{2} + 5}

x \to 0 + lim (x^{2} - ln (x))

\frac{d}{d x} ((x - 4)^{3})

d er i v a t i v e f (x) = \frac{lo g _{9} ( x )}{7 + x ^{9}}

d er i v a t i v e g (x) = 9 e^{x} x

\frac{d}{d x} (\frac{x ^{2}}{1 + 2 tan ( x )})