What is (\partial)/(\partial t)(scos(t)) ?

The answer to (\partial)/(\partial t)(scos(t)) is -ssin(t)

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(\partial)/(\partial t)(scos(t))

\frac{\partial}{\partial t} (s cos (t))

- s sin (t)

Solution steps

\frac{\partial}{\partial t} (s cos (t))

Treat

s

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= s \frac{\partial}{\partial t} (cos (t))

Apply the common derivative:

\frac{\partial}{\partial t} (cos (t)) = - sin (t)

= s (- sin (t))

Simplify

= - s sin (t)

t a y l or x - x^{3}, - 2

\frac{\partial}{\partial y} (3 x z^{2} e^{y^{2}})

d er i v a t i v e f (x) = \frac{1}{x} + \frac{1}{x ^{2}} + \frac{1}{x ^{3}}

\frac{d}{d x} (2 lo g_{10} (x) - 3 x)

\int \frac{2 x ^{2}}{4 x - x ^{2}} d x

What is (\partial)/(\partial t)(scos(t)) ?
The answer to (\partial)/(\partial t)(scos(t)) is -ssin(t)