derivative ((y^3)/3)+1/(4y)

Lösung

ableitung von

(\frac{y ^{3}}{3}) + \frac{1}{4 y}

y^{2} - \frac{1}{4 y ^{2}}

Schritte zur Lösung

\frac{d}{d y} (\frac{y ^{3}}{3} + \frac{1}{4 y})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d y} (\frac{y ^{3}}{3}) + \frac{d}{d y} (\frac{1}{4 y})

\frac{d}{d y} (\frac{y ^{3}}{3}) = y^{2}

\frac{d}{d y} (\frac{1}{4 y}) = - \frac{1}{4 y ^{2}}

= y^{2} - \frac{1}{4 y ^{2}}

p a r i t y f (x) = \frac{x \cdot , ( x )}{1 + x}

x \to - 1 lim (x^{2} - 1)

\int (\frac{1}{4 8 x ^{2}}) d x

d er i v a t i v e f (x) = (3 x + 4) (5 - x^{2}) (4 + x^{2})

x \to \infty lim (e^{x} + 3)