derivative f(x)=3sin(x)+2cos(x)

Lösung

ableitung von

f (x) = 3 sin (x) + 2 cos (x)

3 cos (x) - 2 sin (x)

Schritte zur Lösung

\frac{d}{d x} (3 sin (x) + 2 cos (x))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 sin (x)) + \frac{d}{d x} (2 cos (x))

\frac{d}{d x} (3 sin (x)) = 3 cos (x)

\frac{d}{d x} (2 cos (x)) = - 2 sin (x)

= 3 cos (x) - 2 sin (x)

\frac{d}{d x} (sinh^{3} (2 x))

\int \frac{2 x ^{2} - 25 x - 33}{( x + 1 ) ^{2} ( x - 5 )} d x

3 e^{5 x} \frac{d y}{d x} = \frac{- 25 x}{y ^{2}}, y (0) = 1

x \to 2 lim ((x - 1) (x + 1))

a re a 2 x^{2} + 12, [- 5, 0]