derivative of ln(3x^2+2x)

Lösung

\frac{d}{d x} (ln (3 x^{2} + 2 x))

\frac{6 x + 2}{3 x ^{2} + 2 x}

Schritte zur Lösung

\frac{d}{d x} (ln (3 x^{2} + 2 x))

Wende die Kettenregel an:

\frac{1}{3 x ^{2} + 2 x} \frac{d}{d x} (3 x^{2} + 2 x)

= \frac{1}{3 x ^{2} + 2 x} \frac{d}{d x} (3 x^{2} + 2 x)

\frac{d}{d x} (3 x^{2} + 2 x) = 6 x + 2

= \frac{1}{3 x ^{2} + 2 x} (6 x + 2)

Vereinfache

\frac{1}{3 x ^{2} + 2 x} (6 x + 2) : \frac{6 x + 2}{3 x ^{2} + 2 x}

= \frac{6 x + 2}{3 x ^{2} + 2 x}

x \to 0 + lim (csc (x) - cot (x))

n = 5 \sum \infty \frac{6}{n ^{2} - 1}

ma c l a u r in 5^{x}

s l o p e (- 4, - 4), (- 3, 0)

\frac{\partial}{\partial x} (18 x^{2} y + 12 x y^{2})