What is the derivative of 7e^x+4ln(x) ?

The derivative of 7e^x+4ln(x) is 7e^x+4/x

What is the first derivative of 7e^x+4ln(x) ?

The first derivative of 7e^x+4ln(x) is 7e^x+4/x

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derivative of

7 e^{x} + 4 ln (x)

7 e^{x} + \frac{4}{x}

Solution steps

\frac{d}{d x} (7 e^{x} + 4 ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (7 e^{x}) + \frac{d}{d x} (4 ln (x))

\frac{d}{d x} (7 e^{x}) = 7 e^{x}

\frac{d}{d x} (4 ln (x)) = \frac{4}{x}

= 7 e^{x} + \frac{4}{x}

\int - x e^{\frac{x ^{2}}{2}} d x

x \to 6 lim (x - 6)

y = 3 x^{\frac{2}{3}}

\frac{1}{x ^{0.5}}

\frac{\partial}{\partial y} ((5 x^{3} y + 4 y^{5})^{3})

What is the derivative of 7e^x+4ln(x) ?
The derivative of 7e^x+4ln(x) is 7e^x+4/x
What is the first derivative of 7e^x+4ln(x) ?
The first derivative of 7e^x+4ln(x) is 7e^x+4/x