(\partial)/(\partial x)(3x^2y^4+1)

解答

\frac{\partial}{\partial x} (3 x^{2} y^{4} + 1)

6 x y^{4}

求解步骤

\frac{\partial}{\partial x} (3 x^{2} y^{4} + 1)

将

y

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2} y^{4}) + \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (3 x^{2} y^{4}) = 6 y^{4} x

\frac{\partial}{\partial x} (1) = 0

= 6 y^{4} x + 0

化简

= 6 x y^{4}

\int \frac{1}{x 9 x ^{2} - 4} d x

k = 1 \sum \infty k^{3} \cdot e^{- k^{2}}

\frac{\partial}{\partial x} (4 x^{6} + x y^{3} + 2 y^{4})

\frac{\partial}{\partial y} (y ln (x^{2} y))

\frac{\partial}{\partial x} (x e^{x y} + y e^{- x})