y^{'''}+4y^'=0

Lösung

y^{^{'''}} + 4 y^{^{'}} = 0

y = c_{1} + c_{2} cos (2 t) + c_{3} sin (2 t)

Schritte zur Lösung

y^{'''} (t) + 4 y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} cos (2 t) + c_{3} sin (2 t)

y = c_{1} + c_{2} cos (2 t) + c_{3} sin (2 t)

s l o p e (2.5) (4.7)

\frac{d}{d x} (9 e^{4 x})

\frac{\partial}{\partial x} (\frac{2 x ^{2} + 7 x ^{2} y}{3 x y})

x \to 6 lim (\frac{1}{x - 6})

n = 0 \sum \infty 1 8^{n} x^{n} n!