laplacetransform cos(2t)

解答

拉普拉斯变换

cos (2 t)

\frac{s}{s ^{2} + 4}

求解步骤

L {cos (2 t)}

使用拉普拉斯变换表:

L {cos (a t)} = \frac{s}{s ^{2} + a ^{2}}

L {cos (2 t)} = \frac{s}{s ^{2} + 2 ^{2}}

= \frac{s}{s ^{2} + 2 ^{2}}

= \frac{s}{s ^{2} + 4}

l a pl a ce t r an s f or m s^{2} + 4 s + 13 s^{2} + 4 s + 13

n = 0 \sum \infty (n + 1) x^{n}

\frac{d}{d x} (\frac{x ^{2} - x + 1}{x ^{2} + 1})

\frac{d y}{d x} + \frac{3}{3.5} y = 9.8

\frac{\partial}{\partial z} (z ln (x^{2} y cos (z)))