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人気のある微分積分 >

(dP)/(dt)=kP^{1.01},P(0)=10

解

\frac{d P}{d t} = k P^{1.01}, P (0) = 10

解

P = \frac{10 0 ^{100}}{( k t - 2 ^{1.99} \cdot 5 ^{1.99} ) ^{100}}

解答ステップ

\frac{d P}{d t} = k P^{1.01}

分離可能 ODE を解く:

P = \frac{10 0 ^{100}}{( k t - 2 ^{1.99} \cdot 5 ^{1.99} ) ^{100}}

P = \frac{10 0 ^{100}}{( k t - 2 ^{1.99} \cdot 5 ^{1.99} ) ^{100}}

グラフ

人気の例

(d^2)/(dx^2)(cos(5x))

\frac{d ^{2}}{d x ^{2}} (cos (5 x))

limit as x approaches 0 of (a^x-b^x)/x

x \to 0 lim (\frac{a ^{x} - b ^{x}}{x})

normal y=2x^2,(-2,8)

n or ma l y = 2 x^{2}, (- 2, 8)

integral from 0 to 5 of (t^2+2t-15)

\int_{0}^{5} (t^{2} + 2 t - 15) d t

limit as t approaches 0 of 5/t-5/(e^t-1)

t \to 0 lim (\frac{5}{t} - \frac{5}{e ^{t} - 1})