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Beliebt Rechnen >

y^{''}+2y^'+y=0,y(1)=1,y^'(1)=0

Lösung

y^{^{''}} + 2 y^{^{'}} + y = 0, y (1) = 1, y^{^{'}} (1) = 0

Lösung

y = e^{- t + 1} t

Schritte zur Lösung

y^{''} (t) + 2 y^{'} (t) + y = 0

Solve linear ODE:

y = e^{- t + 1} t

y = e^{- t + 1} t

Graph

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