What is the derivative of 5^{5x} ?

The derivative of 5^{5x} is ln(5)*5^{5x+1}

What is the first derivative of 5^{5x} ?

The first derivative of 5^{5x} is ln(5)*5^{5x+1}

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\frac{d}{d x} (5^{5 x})

ln (5) \cdot 5^{5 x + 1}

Solution steps

\frac{d}{d x} (5^{5 x})

Simplify

5^{5 x} : 312 5^{x}

= \frac{d}{d x} (312 5^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 312 5^{x} ln (3125)

Simplify

312 5^{x} ln (3125) : ln (5) \cdot 5^{5 x + 1}

= ln (5) \cdot 5^{5 x + 1}

\int \frac{1}{3} tan (3 x) d x

\int cos^{2} (θ) - sin^{2} (θ) d θ

x \to 0 lim ((1 - 8 x)^{\frac{1}{x}})

\frac{d y}{d x} = e^{5 y} sin (6 x)

\frac{d}{d x} (\frac{sin ( x )}{tan ( x ) + x})

What is the derivative of 5^{5x} ?
The derivative of 5^{5x} is ln(5)*5^{5x+1}
What is the first derivative of 5^{5x} ?
The first derivative of 5^{5x} is ln(5)*5^{5x+1}