(3x+2y+1)dx-(3x+2y-1)dy=0

Lösung

(3 x + 2 y + 1) \cdot d x - (3 x + 2 y - 1) \cdot d y = 0

y = - \frac{2 W ( \frac{1}{4 e ^{\frac{25 x + c _{1}}{4}}} ) - 3}{5} - \frac{3 x}{2} - \frac{1}{2}

Schritte zur Lösung

(3 x + 2 y + 1) \cdot d x - (3 x + 2 y - 1) \cdot d y = 0

Solve using substitution:

y = - \frac{2 W ( \frac{1}{4 e ^{\frac{25 x + c _{1}}{4}}} ) - 3}{5} - \frac{3 x}{2} - \frac{1}{2}

y = - \frac{2 W ( \frac{1}{4 e ^{\frac{25 x + c _{1}}{4}}} ) - 3}{5} - \frac{3 x}{2} - \frac{1}{2}

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