integral of zcos(z)

解答

\int z cos (z) d z

z sin (z) + cos (z) + C

求解步骤

\int z cos (z) d z

使用分布积分法

= z sin (z) - \int sin (z) d z

\int sin (z) d z = - cos (z)

= z sin (z) - (- cos (z))

化简

= z sin (z) + cos (z)

解答补常数

= z sin (z) + cos (z) + C

9 y^{^{''}} + 10 y = 0, y (π) = 1

\frac{d}{d x} (9 x^{\frac{7}{5}} - 5 x^{2} + 1 0^{4})

x \to 0 + lim (- x + 7)

\frac{d ^{2} y}{d x ^{2}} = e^{5 x^{2}}

\frac{d}{d t} (\frac{tan ^{2} ( 3 t )}{t ^{2} + sec ^{2} ( t ) + 1})