integral of 5cos(v)-7/(sqrt(1-v^2))

Lösung

\int 5 cos (v) - \frac{7}{1 - v ^{2}} d v

5 sin (v) - 7 arcsin (v) + C

Schritte zur Lösung

\int 5 cos (v) - \frac{7}{1 - v ^{2}} d v

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 5 cos (v) d v - \int \frac{7}{1 - v ^{2}} d v

\int 5 cos (v) d v = 5 sin (v)

\int \frac{7}{1 - v ^{2}} d v = 7 arcsin (v)

= 5 sin (v) - 7 arcsin (v)

Füge eine Konstante zur Lösung hinzu

= 5 sin (v) - 7 arcsin (v) + C

\frac{\partial}{\partial y} (4 - x^{2} - 5 y^{2})

\frac{\partial}{\partial x} (5 e^{x})

in v erse l a pl a ce \frac{s - 3}{s ^{2} - 4 s + 3}

x \to 0 lim (\frac{ln ( x ^{2} + 1 )}{x})

a re a x^{2}, x - 4, - 4, 4