limit as x approaches-0 of e^{1/x}

Lösung

x \to - 0 lim (e^{\frac{1}{x}})

divergiert

Schritte zur Lösung

x \to - 0 lim (e^{\frac{1}{x}})

Wenn

x \to a - lim f (x) \neq = x \to a + lim f (x)

dann gibt es keine Grenze

x \to - 0 + lim (e^{\frac{1}{x}}) = \infty

x \to - 0 - lim (e^{\frac{1}{x}}) = 0

= divergiert

\frac{d}{d x} (c^{1} cos (x) + c^{2} sin (x))

x \to - 4 lim (12 x + 1)

\int \frac{1}{x ln ^{2} ( x ) + 1} d x

\int \frac{4 x}{( x ^{2} + 1 ) ^{2}} d x

\frac{d}{d θ} (sec^{2} (m θ))