sum from n=1 to infinity of 1/(n^2+5n+6)

Lösung

n = 1 \sum \infty \frac{1}{n ^{2} + 5 n + 6}

\frac{1}{3}

Dezimale

0.33333 \dots

Schritte zur Lösung

n = 1 \sum \infty \frac{1}{n ^{2} + 5 n + 6}

Teleskopreihen-Test anwenden:

\frac{1}{3}

= \frac{1}{3}

\frac{d}{d x} (4 + ln (x))

y^{^{'}} = y (x y^{6} + 1)

\int_{0}^{17} 2 π x (17 x - x^{2}) d x

x \to a lim (\frac{sec ( x ) - sec ( a )}{x - a})

a re a y = 6 - ln (x + 1), y = ln (x + 1), x = 0