derivative of tan^{cos(x}(x))

Lösung

\frac{d}{d x} (tan^{c o s (x)} (x))

tan^{c o s (x)} (x) (- sin (x) ln (tan (x)) + 2 csc (2 x) cos (x))

Schritte zur Lösung

\frac{d}{d x} (tan^{c o s (x)} (x))

Wende Exponentenregel an:

a^{b} = e^{b l n (a)}

tan^{c o s (x)} (x) = e^{c o s (x) l n (t a n (x))}

= \frac{d}{d x} (e^{c o s (x) l n (t a n (x))})

Wende die Kettenregel an:

e^{c o s (x) l n (t a n (x))} \frac{d}{d x} (cos (x) ln (tan (x)))

= e^{c o s (x) l n (t a n (x))} \frac{d}{d x} (cos (x) ln (tan (x)))

\frac{d}{d x} (cos (x) ln (tan (x))) = - sin (x) ln (tan (x)) + 2 csc (2 x) cos (x)

= e^{c o s (x) l n (t a n (x))} (- sin (x) ln (tan (x)) + 2 csc (2 x) cos (x))

e^{c o s (x) l n (t a n (x))} = tan^{c o s (x)} (x)

= tan^{c o s (x)} (x) (- sin (x) ln (tan (x)) + 2 csc (2 x) cos (x))

\frac{\partial}{\partial x} (x y sin (z))

\frac{d}{d x} (4 tan (x) + cot (x))

\frac{\partial}{\partial x} (5 x^{3} y)

s l o p e (- 41.38, 4.9), (2.38, 3.7)

\frac{d}{d x} (x + \frac{1}{4} sin^{2} (2 x))