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人気のある微分積分 >

sum from n=1 to infinity of (1/2)^n

解

n = 1 \sum \infty (\frac{1}{2})^{n}

解

1

解答ステップ

n = 1 \sum \infty (\frac{1}{2})^{n}

n = k \sum \infty (a_{n}) = n = 0 \sum \infty (a_{n}) - a_{0} - a_{1} - \dots a_{k - 1}

= n = 0 \sum \infty (\frac{1}{2})^{n} - (\frac{1}{2})^{0}

n = 0 \sum \infty (\frac{1}{2})^{n} = 2

= 2 - (\frac{1}{2})^{0}

簡素化

= 1

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