(dy)/(dx)=0.0225y+0.0003y^2

解答

\frac{d y}{d x} = 0.0225 y + 0.0003 y^{2}

y = \frac{74.99999 \dots e ^{0.0225 x + 0.0225 c_{1}}}{1 - e ^{0.0225 (x + c_{1})}}

求解步骤

\frac{d y}{d x} = 0.0225 y + 0.0003 y^{2}

求解可分离方程:

y = \frac{74.99999 \dots e ^{0.0225 x + 0.0225 c_{1}}}{1 - e ^{0.0225 (x + c_{1})}}

y = \frac{74.99999 \dots e ^{0.0225 x + 0.0225 c_{1}}}{1 - e ^{0.0225 (x + c_{1})}}

\frac{d}{d x} (\frac{2}{( x - 2 ) ^{3}})

\frac{\partial}{\partial x} (x^{2} y + 3 x y + y^{2})

x \to \infty lim ((\frac{( 2 x - 3 )}{( 2 x + 5 )})^{2 x + 1})

a re a x = \frac{4}{y}, x = \frac{y}{8}, x = 8 y

\frac{\partial}{\partial x} (\frac{3 x + t}{x - 5 t})