What is the integral of e^xcos(y)+yz ?

The integral of e^xcos(y)+yz is cos(y)e^x+yzx+C

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integral of e^xcos(y)+yz

\int e^{x} cos (y) + yz d x

cos (y) e^{x} + yz x + C

Solution steps

\int e^{x} cos (y) + yz d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int cos (y) e^{x} d x + \int yz d x

\int cos (y) e^{x} d x = cos (y) e^{x}

\int yz d x = yz x

= cos (y) e^{x} + yz x

Add a constant to the solution

= cos (y) e^{x} + yz x + C

\frac{d}{d x} (x!)

\frac{d}{d x} (lo g_{3} (x + 3))

\int 6 x^{5} (x^{6})^{5} d x

\int \frac{3 t ^{2} + 2}{( t ^{3} + 2 t + 3 ) ^{5}} d t

\frac{\partial}{\partial y} (cos (x + y))

What is the integral of e^xcos(y)+yz ?
The integral of e^xcos(y)+yz is cos(y)e^x+yzx+C