3y^{''}+4y^'=0

Lösung

3 y^{^{''}} + 4 y^{^{'}} = 0

y = c_{1} + c_{2} e^{- \frac{4 t}{3}}

Schritte zur Lösung

3 y^{''} (t) + 4 y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- \frac{4 t}{3}}

y = c_{1} + c_{2} e^{- \frac{4 t}{3}}

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