t^2(dx)/(dt)=2tx+1

Lösung

t^{2} \frac{d x}{d t} = 2 t x + 1

x = - \frac{1}{3 t} + c_{1} t^{2}

Schritte zur Lösung

t^{2} \frac{d x}{d t} = 2 t x + 1

Solve linear ODE:

x = - \frac{1}{3 t} + c_{1} t^{2}

x = - \frac{1}{3 t} + c_{1} t^{2}

\int \frac{1}{x ^{2} ( 1 + \frac{1}{x} ) ^{3}} d x

\int_{0}^{1} 5 x^{4} e^{- x} d x

\int \frac{4}{x ^{2} - 14 x + 49} d x

\frac{\partial}{\partial x} (cos^{2} (5 x))

5 y^{^{''}} + y^{^{'}} = - 6 x, y (0) = 0, y^{^{'}} (0) = - 20