-4x^2y+y^'=-10x^2

Lösung

- 4 x^{2} y + y^{^{'}} = - 10 x^{2}

y = \frac{e ^{\frac{4 x ^{3} + c _{1}}{3}}}{2} + \frac{5}{2}

Schritte zur Lösung

- 4 x^{2} y + y^{'} (x) = - 10 x^{2}

Solve separable ODE:

y = \frac{e ^{\frac{4 x ^{3} + c _{1}}{3}}}{2} + \frac{5}{2}

y = \frac{e ^{\frac{4 x ^{3} + c _{1}}{3}}}{2} + \frac{5}{2}

f (x) = \frac{e ^{x}}{x}

d er i v a t i v e 8 t

\frac{d ^{2}}{d x ^{2}} (x + 7)

\int x^{2} (x^{3} + 1)^{2} d x

g (x) = \frac{5}{6 x ^{3}}