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Beliebt Rechnen >

inverselaplace (3e^{-pis})/(s^2+9)

Lösung

inverse laplace transformation

\frac{3 e ^{- π s}}{s ^{2} + 9}

Lösung

H (t - π) sin (3 (t - π))

Schritte zur Lösung

L^{- 1} {\frac{3 e ^{- π s}}{s ^{2} + 9}}

Wende inverse Transformationsregel an: if

L^{- 1} {F (s)} = f (t)

dann

L^{- 1} {e^{- a s} F (s)} = H (t - a) f (t - a)

Wo

H (t)

Heaviside (Schritt) Funktion ist

= H (t - π) L^{- 1} {\frac{3}{s ^{2} + 9}} (t - π)

L^{- 1} {\frac{3}{s ^{2} + 9}} : sin (3 t)

= H (t - π) sin (3 (t - π))

Beliebte Beispiele

tangent f(x)=4x^2-1,(-6,3)

t an g e n t f (x) = 4 x^{2} - 1, (- 6, 3)

y^'=(x+y-2)^2,y(0)=0

y^{^{'}} = (x + y - 2)^{2}, y (0) = 0

derivative 2cos(pit)

d er i v a t i v e 2 cos (π t)

(\partial)/(\partial y)((x-5)^{1/4}y^{1/4})

\frac{\partial}{\partial y} ((x - 5)^{\frac{1}{4}} y^{\frac{1}{4}})

derivative of x^{sqrt(x)+1}

\frac{d}{d x} (x^{x + 1})