integral of 1+x^3

Lösung

\int 1 + x^{3} d x

x + \frac{x ^{4}}{4} + C

Schritte zur Lösung

\int 1 + x^{3} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d x + \int x^{3} d x

\int 1 d x = x

\int x^{3} d x = \frac{x ^{4}}{4}

= x + \frac{x ^{4}}{4}

Füge eine Konstante zur Lösung hinzu

= x + \frac{x ^{4}}{4} + C

t an g e n t f (x) = \frac{x ^{2}}{x - 3}

d er i v a t i v e e^{2 x} cos (3 x)

t an g e n t f (x) = 4 tan (x), at x = \frac{π}{3}

\int_{0}^{3} π (9 - x^{2})^{2} d x

x \to 0 + lim (\frac{x ^{3} + 3}{x})