(\partial)/(\partial y)(e^x+cos(y))

Lösung

\frac{\partial}{\partial y} (e^{x} + cos (y))

- sin (y)

Schritte zur Lösung

\frac{\partial}{\partial y} (e^{x} + cos (y))

Behandle

x

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (e^{x}) + \frac{\partial}{\partial y} (cos (y))

\frac{\partial}{\partial y} (e^{x}) = 0

\frac{\partial}{\partial y} (cos (y)) = - sin (y)

= 0 - sin (y)

Vereinfache

= - sin (y)

\int \frac{1}{x ln ( x ) - x} d x

\frac{\partial}{\partial x} (x e^{y} - e^{z})

im pl i c i t \frac{d y}{d x}, y e^{x} = y

\frac{d}{d x} ((3 x + 1) \frac{( x ^{2} + 4 )}{( 6 x - 5 )})

\int \frac{sin ( 2 x )}{sin ( x )} d x