derivative f(x)=θcos(θ)

Lösung

ableitung von

f (x) = θ cos (θ)

\frac{d θ}{d x} = 0

Schritte zur Lösung

f (x) = θ cos (θ)

Behandle

θ

wie

θ (x)

Beide Seiten differenzieren:

0 = cos (θ) \frac{d θ}{d x} - sin (θ) \frac{d θ}{d x} θ

Isoliere

\frac{d θ}{d x} : \frac{d θ}{d x} = 0

\frac{d θ}{d x} = 0

\frac{d}{d x} (x^{3} - 2)

a re a f (x) = x^{2} + 4, g (x) = - x^{2} - 1, x = - 2, x = 3

d er i v a t i v e f (x) = \frac{x ^{2} - 1}{2 x - 3}

\frac{d ^{2} y}{d t ^{2}} - 4 \frac{d y}{d t} - 5 y = 0

\frac{d}{d x} (\frac{x ^{4} + 3 x ^{2}}{( x ^{2} + 1 ) ^{2}})