derivative of 1/(1+4x^2-arctan(2x))

Lösung

\frac{d}{d x} (\frac{1}{1 + 4 x ^{2}} - arctan (2 x))

- \frac{8 x}{( 1 + 4 x ^{2} ) ^{2}} - \frac{2}{4 x ^{2} + 1}

Schritte zur Lösung

\frac{d}{d x} (\frac{1}{1 + 4 x ^{2}} - arctan (2 x))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{1 + 4 x ^{2}}) - \frac{d}{d x} (arctan (2 x))

\frac{d}{d x} (\frac{1}{1 + 4 x ^{2}}) = - \frac{8 x}{( 1 + 4 x ^{2} ) ^{2}}

\frac{d}{d x} (arctan (2 x)) = \frac{2}{4 x ^{2} + 1}

= - \frac{8 x}{( 1 + 4 x ^{2} ) ^{2}} - \frac{2}{4 x ^{2} + 1}

l a pl a ce t r an s f or m e^{- t} sin^{2} (t)

x y^{^{'''}} - \frac{2}{x} y^{^{'}} = 0

\frac{d}{d x} (sin (p (x)) i x)

d er i v a t i v e cos (8 x)

in v erse l a pl a ce \frac{s}{( s - 3 ) ^{2}}