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受欢迎的微积分 >

tangent (1+x)cos(x)

解答

切线

(1 + x) cos (x)

解答

y = (cos (a_{0}) - sin (a_{0}) (1 + a_{0})) x + cos (a_{0}) + a_{0} sin (a_{0}) + a_{0}^{2} sin (a_{0})

求解步骤

计算在一般点

x = a_{0}

的切线

找到切点:

(a_{0}, (1 + a_{0}) cos (a_{0}))

计算

y = (1 + x) cos (x)

的斜率:

\frac{d y}{d x} = cos (x) - sin (x) (1 + x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = cos (a_{0}) - sin (a_{0}) (1 + a_{0})

找到斜率 m=

cos (a_{0}) - sin (a_{0}) (1 + a_{0})

且穿过

(a_{0}, (1 + a_{0}) cos (a_{0}))

的直线:

y = (cos (a_{0}) - sin (a_{0}) (1 + a_{0})) x + cos (a_{0}) + a_{0} sin (a_{0}) + a_{0}^{2} sin (a_{0})

y = (cos (a_{0}) - sin (a_{0}) (1 + a_{0})) x + cos (a_{0}) + a_{0} sin (a_{0}) + a_{0}^{2} sin (a_{0})

作图

流行的例子

integral of 7/(16+9r^2)

\int \frac{7}{16 + 9 r ^{2}} d r

tangent y= 7/(sqrt(x)),(1,7)

t an g e n t y = \frac{7}{x}, (1, 7)

derivative h(t)=(t^4-1)^3(t^3+1)^4

d er i v a t i v e h (t) = (t^{4} - 1)^{3} (t^{3} + 1)^{4}

derivative of xe^{-1/2 x}

\frac{d}{d x} (x e^{- \frac{1}{2} x})

(\partial)/(\partial x)(ln(x+7y+6z))

\frac{\partial}{\partial x} (ln (x + 7 y + 6 z))