What is the integral from-1 to 3 of (x+1)^3 ?

The integral from-1 to 3 of (x+1)^3 is 64

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 3 of (x+1)^3

\int_{- 1}^{3} (x + 1)^{3} d x

64

Solution steps

\int_{- 1}^{3} (x + 1)^{3} d x

Apply u-substitution

: \int_{0}^{4} u^{3} d u

= \int_{0}^{4} u^{3} d u

Apply the Power Rule

: [\frac{u ^{4}}{4}]_{0}^{4}

= [\frac{u ^{4}}{4}]_{0}^{4}

Compute the boundaries:

64

= 64

(x^{4} + 2 y) d x - x d y = 0

0.2 x^{3} \cdot 3^{x}

x \to \infty lim (- 1^{2 x})

\int e^{a}

\int (x + \frac{sin ( 2 x )}{y}) d x

What is the integral from-1 to 3 of (x+1)^3 ?
The integral from-1 to 3 of (x+1)^3 is 64