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人気のある微分積分 >

integral from-1 to 6 of (9y)/(y^2-5y-14)

解

\int_{- 1}^{6} \frac{9 y}{y ^{2} - 5 y - 14} d y

解

- 15 ln (2)

+1

十進法表記

- 10.39720 \dots

解答ステップ

\int_{- 1}^{6} \frac{9 y}{y ^{2} - 5 y - 14} d y

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int_{- 1}^{6} \frac{y}{y ^{2} - 5 y - 14} d y

以下の部分分数を得る:

\frac{y}{y ^{2} - 5 y - 14} : \frac{2}{9 ( y + 2 )} + \frac{7}{9 ( y - 7 )}

= 9 \cdot \int_{- 1}^{6} \frac{2}{9 ( y + 2 )} + \frac{7}{9 ( y - 7 )} d y

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 9 (\int_{- 1}^{6} \frac{2}{9 ( y + 2 )} d y + \int_{- 1}^{6} \frac{7}{9 ( y - 7 )} d y)

\int_{- 1}^{6} \frac{2}{9 ( y + 2 )} d y = \frac{2}{3} ln (2)

\int_{- 1}^{6} \frac{7}{9 ( y - 7 )} d y = - \frac{7}{3} ln (2)

= 9 (\frac{2}{3} ln (2) - \frac{7}{3} ln (2))

簡素化

9 (\frac{2}{3} ln (2) - \frac{7}{3} ln (2)) : - 15 ln (2)

= - 15 ln (2)

グラフ

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