x^3+3y-xy^'=0

Lösung

x^{3} + 3 y - x y^{^{'}} = 0

y = ln (x) x^{3} + c_{1} x^{3}

Schritte zur Lösung

x^{3} + 3 y - x y^{'} (x) = 0

Solve linear ODE:

y = ln (x) x^{3} + c_{1} x^{3}

y = ln (x) x^{3} + c_{1} x^{3}

x \to \frac{π}{2} lim (tan^{2} (x))

y^{^{''}} + 2 y^{^{'}} + y = sin (x) + 6 cos (2 x)

x \to - 2 lim (x^{3} + 6 x^{2} - 16)

\int \frac{( cos ^{2} ( x ) )}{sin ( x )} d x

\int \frac{1}{( 2 x + 3 ) ^{2}} d x