What is the domain of sqrt(25y^2-9y^2),y>0 ?

The domain of sqrt(25y^2-9y^2),y>0 is y>0

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domain of sqrt(25y^2-9y^2),y>0

domain

25 y^{2} - 9 y^{2}, y > 0

y > 0

Interval Notation

(0, \infty)

Solution steps

Set the domain to the given interval

y > 0

Find non-negative values for radicals:

- \infty < y < \infty

Join real regions with the domain:

True for all

y \in R and y > 0

y > 0

f (x) = \frac{2 x ^{2}}{x ^{4} + 1}

f (x) = (5 x + 4)^{2}

f (x) = (x + 1)^{4} (x - 3)^{5} (x - 2)

f (n) = 2^{2 n + 1}

f (θ) = \frac{6}{2 cos ( θ ) - 3 sin ( θ )}

What is the domain of sqrt(25y^2-9y^2),y>0 ?
The domain of sqrt(25y^2-9y^2),y>0 is y>0