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Popular >

f(x)=(x^2+4)/(4x^2-4x-8)

Solution

f (x) = \frac{x ^{2} + 4}{4 x ^{2} - 4 x - 8}

Solution

Domain : x < - 1 or - 1 < x < 2 or x > 2

Range : f (x) \leq \frac{- 10 - 1}{9} or f (x) \geq \frac{10 - 1}{9}

Y Intercepts : (0, - \frac{1}{2})

Asymptotes : Vertical x = - 1, x = 2, Horizontal y = \frac{1}{4}

Extreme Points : Minimum (- 2 (3 + 10), \frac{10 - 1}{9}), Maximum (2 (10 - 3), - \frac{1 + 10}{9})

+1

Interval Notation

Domain : (- \infty, - 1) \cup (- 1, 2) \cup (2, \infty)

Range : (- \infty, \frac{- 10 - 1}{9}] \cup [\frac{10 - 1}{9}, \infty)

Solution steps

Domain of

\frac{x ^{2} + 4}{4 x ^{2} - 4 x - 8} : x < - 1 or - 1 < x < 2 or x > 2

Range of

\frac{x ^{2} + 4}{4 x ^{2} - 4 x - 8} : f (x) \leq \frac{- 10 - 1}{9} or f (x) \geq \frac{10 - 1}{9}

Axis interception points of

\frac{x ^{2} + 4}{4 x ^{2} - 4 x - 8} :

Y Intercepts

: (0, - \frac{1}{2})

Asymptotes of

\frac{x ^{2} + 4}{4 x ^{2} - 4 x - 8} :

Vertical

: x = - 1, x = 2,

Horizontal

: y = \frac{1}{4}

Extreme Points of

\frac{x ^{2} + 4}{4 x ^{2} - 4 x - 8} :

Minimum

(- 2 (3 + 10), \frac{10 - 1}{9}),

Maximum

(2 (10 - 3), - \frac{1 + 10}{9})

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Frequently Asked Questions (FAQ)

What is the f(x)=(x^2+4)/(4x^2-4x-8) ?
The f(x)=(x^2+4)/(4x^2-4x-8) is