invers f(x)=(x+3)^2-1

Lösung

invers

f (x) = (x + 3)^{2} - 1

x + 1 - 3, - x + 1 - 3

Schritte zur Lösung

y = (x + 3)^{2} - 1

Ersetze

x

durch

y

x = (y + 3)^{2} - 1

Löse nach

y, x = (y + 3)^{2} - 1

x + 1 - 3, - x + 1 - 3

d o main y = \frac{3}{4} - 2 - x

e x t re m e f (x) = 2 x^{2} + x + 2, - 1 \leq x \leq 3

e x t re m e f (x) = sin (x), 0 \leq x < π^{2}

p a r i t y \frac{- x ^{2} - x + 6}{x ^{2} + 3 x - 4}

in v erse f (x) = 2 x - 1 + 3