slopeintercept y=-2/5 x+8

解答

斜率截距

y = - \frac{2}{5} x + 8

y = - \frac{2}{5} x + 8

求解步骤

y = - \frac{2}{5} x + 8

对于

y = mx + b

形式的直线方程，斜率为

m

且

y

轴截距为

b

y = - \frac{2}{5} x + 8

v er t i ces y = x^{2} - 6 x + 7

cr i t i c a l \frac{x ^{3}}{x ^{2} - 1}

r an g e f (x) = ∣ x - 2 ∣

in t erce pt s x^{3} - 4 x^{2} + 8 x - 5

e x t re m e 6 x^{4} + 8 x^{3}