What is the inverse of f(x)=x^2-4x-1 ?

The inverse of f(x)=x^2-4x-1 is 2+sqrt(x+5),2-sqrt(x+5)

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inverse of f(x)=x^2-4x-1

inverse

f (x) = x^{2} - 4 x - 1

2 + x + 5, 2 - x + 5

Solution steps

y = x^{2} - 4 x - 1

Replace

x

with

y

x = y^{2} - 4 y - 1

Solve for

y, x = y^{2} - 4 y - 1

2 + x + 5, 2 - x + 5

f (x) = 3 x + 4 x + 6

f (x) = (x - 7) (x - 9)

f (x) = \frac{2 x + 5}{x + 1}

2 (3^{x}) + 1

What is the inverse of f(x)=x^2-4x-1 ?
The inverse of f(x)=x^2-4x-1 is 2+sqrt(x+5),2-sqrt(x+5)